x^2-25x-13=0

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Solution for x^2-25x-13=0 equation: 



x^2-25x-13=0

a = 1; b = -25; c = -13;
Δ = b2-4ac
Δ = -252-4·1·(-13)
Δ = 677
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{677}}{2*1}=\frac{25-\sqrt{677}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{677}}{2*1}=\frac{25+\sqrt{677}}{2}
$

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